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Algebra questions 2

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4. A man has a number of ducks costing $10 each and three times as many chickens costing $6 each. If the total cost of ducks and chickens is $420, find the number of chickens the man has.5. A shopkeeper buys some eggs at 15 cents each. Six of them are broken while the rest are sold at 20 cents each. If he makes a... 顯示更多 4. A man has a number of ducks costing $10 each and three times as many chickens costing $6 each. If the total cost of ducks and chickens is $420, find the number of chickens the man has. 5. A shopkeeper buys some eggs at 15 cents each. Six of them are broken while the rest are sold at 20 cents each. If he makes a profit of $4.8, find how many eggs he bought.

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最佳解答:

4. 3x=y, 10x+6y = 420 so, 10x + 18x = 420 28x = 420 x = 15, y = 45 The number of chickens the man has is 45. 5. 0.2(x-6) - 0.15x = 4.8 0.2x-1.2-0.15x = 4.8 0.2x - 0.15x = 4.8 + 1.2 0.05x = 6 x = 120 The number of eggs he bought is 120.

其他解答:

4. A man has a number of ducks costing $10 each and three times as many chickens costing $6 each. If the total cost of ducks and chickens is $420, find the number of chickens the man has. 設這人有 x 隻鴨，則 10x + 6(3x) = 420 10x + 18x = 420 28x = 420 x = 28 這人有鴨 28隻 有雞 3x = 3*28 = 84隻 5. A sho*****eeper buys some eggs at 15 cents each. Six of them are broken while the rest are sold at 20 cents each. If he makes a profit of $4.8, find how many eggs he bought. 設他買了 x 隻蛋 成本為 15x 它賣了 x – 6 隻蛋， 收回 20(x-6) 依題意 20(x-6) – 15x = 48*100 20x – 120 – 15x = 4800 5x = 4920 x = 984隻D1B39E804036C6BD