標題:
- 融資融券的手續費怎算
- 收購二手朔膠桶
- Any recommend Buffet amt $ under 400 --
- 幫幫手!!請大家睇下問題內容..thx... (20分)
- 請問Excel達人函數問題
- 我想換顯卡和記憶體預算大約3000左右
- 有關帕德嫩神廟
- 想問一問 香港醫藥援助會牙科門診服務
- 化學重頭來~麻煩幫我計算幾個化學比熱的問題~~^^”
- 今年餐旅統測...(5點)
此文章來自奇摩知識+如有不便請留言告知
F.6 Statics
發問:
A uniform ladder 5.0m long and having mass 40kg with its upper end against a smooth vertical wall and with its lower end 3.0m from the wall on rough ground. Find the magnitude and direction of the force exerted at the bottom of the ladder.
最佳解答:
From the given, we have the height of the ladder top is 4 m from the ground. Then with reference to the diagram below: 圖片參考:http://i388.photobucket.com/albums/oo325/loyitak1990/Oct09/Crazymech2.jpg The force from the wall should be horizontal since it is smooth and hence no friction. In translational, we have F = f and R = W in magnitude Therefore R = 400 N Then taking moment about the bottom of the ladder: 4F = 1.5W F = 150 N f = 150 N So by Pyth. theorem, the amgnitude of the force exerted at the bottom of the ladder should be √(R2 + f2) = 427 N With inclination at tan-1 (R/f) = 69.4 deg.
其他解答:
這裏可以幫到你 http://yayantw.test.hansawell.net/yahoo.com.hk/hk/auction/1118037410D1B39E804036C6BD