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http://upload.lsforum.net/users/public/o29313RWf209.png
最佳解答:
At t = 0+ s, all capacitors behave as short-curcuit. For the right hand loop, v3 = 100 v, i4 = 100/ 50 A = 2 A , v4 = 0 v For the middle loop, v2 = 100 v, i3 = 100/ 25 A = 4 A , i2 = 25 A For the left loop, v1 = 0 v, i1 = 0 A , After the switch closes for a long time, all capacitors are fully charged and behave as open circuit. For the right hand loop, v4 = 100 v, v3 = 0 v, i4 = 0 A For the loop to the left of the battery, i3 = i1 = 100/(25 + 10) A = 2.857 A v1 = 2.857 x 10 v = 28.57 v, v2 = 2.857 x 25 v = 71.425 v i2 = 0 A
其他解答:D1B39E804036C6BD
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Physics problems!!!發問:
http://upload.lsforum.net/users/public/o29313RWf209.png
最佳解答:
At t = 0+ s, all capacitors behave as short-curcuit. For the right hand loop, v3 = 100 v, i4 = 100/ 50 A = 2 A , v4 = 0 v For the middle loop, v2 = 100 v, i3 = 100/ 25 A = 4 A , i2 = 25 A For the left loop, v1 = 0 v, i1 = 0 A , After the switch closes for a long time, all capacitors are fully charged and behave as open circuit. For the right hand loop, v4 = 100 v, v3 = 0 v, i4 = 0 A For the loop to the left of the battery, i3 = i1 = 100/(25 + 10) A = 2.857 A v1 = 2.857 x 10 v = 28.57 v, v2 = 2.857 x 25 v = 71.425 v i2 = 0 A
其他解答:D1B39E804036C6BD
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