標題:
math(easy`easy(have 10 marks~~!!要例式!!thanks!!
發問:
1)a girl`s age is2 years more than 1/2 of her mother`s age.if the sum of their ages is 62,find their ages.2)a sum of money is to be evenly shared among 10person .however,two of them are absent,so each of the 8 attendees gets $30 more find the total amount of money.3)peter has $9 more than paul,and philip`s... 顯示更多 1)a girl`s age is2 years more than 1/2 of her mother`s age.if the sum of their ages is 62,find their ages. 2)a sum of money is to be evenly shared among 10person .however,two of them are absent,so each of the 8 attendees gets $30 more find the total amount of money. 3)peter has $9 more than paul,and philip`s is1/3 of peter`s.how much money does each of them have if they have a total of $61?
1. Let y be the age of the girl, then (62 - y) be the age of her mother y -2 = 1/2 (62 - y) 2(y - 2) = 62 - y 2y - 4 = 62 - y 3y = 66 y = 22 Hence, the age of the girl is 22 & the age of her mother is (62 - 22) = 40. 2. Let y be the total amount of money, y/10 + 30 = y/8 4y + 1200 = 5y y = 1200 Hence, the total amount of money is $1200. 3. Let y be Peter has, then ( y - 9 ) be Paul has & y/3 be Philip has, y + ( y - 9 ) + y/3 = 61 2y - 9 + y/3 = 61 2y + y/3 = 70 6y + y = 210 7y = 210 y = 30 Hence, Peter has $30, Paul has (30 - 9) = $21, Philip has (30/3) = $10
其他解答:
1)Let x be the girl's age and y be her mother's age x-y/2=2...(1) x+y=62...(2) From (2) x=62-y...(3) Put (3) into (1), 62-y-y/2=2 124-2y-y=4 -3y=-120 y=40 Put y=40 into (2) x+40=62 x=22 Therefore, the girl is 22 years old and her mother is 40 years old. 2)Because each of the 8 attendees gets $30 more after two absent, so two absent have 8*30=$240 and each of them have $120 so the total amount of money is $120*10=$1200 3)Let x be the money that Peter has, y be the money that Paul has and z be the money that Philip has x-y=9...(1) x/3=z...(2) x+y+z=61...(3) From (1), y=x-9...(4) Put (4) and (2) into (3) x+(x-9)+x/3=61 3x+3x-27+x=183 7x-27=183 7x=210 x=30 Put x=30 into (1), 30-y=9 -y=-21 y=21 Put x=30 into (2), 30/3=z z=10 Therefore, Peter has $30, Paul has $21 and Philip has $10.34CDDE348BEB263C
math(easy`easy(have 10 marks~~!!要例式!!thanks!!
發問:
1)a girl`s age is2 years more than 1/2 of her mother`s age.if the sum of their ages is 62,find their ages.2)a sum of money is to be evenly shared among 10person .however,two of them are absent,so each of the 8 attendees gets $30 more find the total amount of money.3)peter has $9 more than paul,and philip`s... 顯示更多 1)a girl`s age is2 years more than 1/2 of her mother`s age.if the sum of their ages is 62,find their ages. 2)a sum of money is to be evenly shared among 10person .however,two of them are absent,so each of the 8 attendees gets $30 more find the total amount of money. 3)peter has $9 more than paul,and philip`s is1/3 of peter`s.how much money does each of them have if they have a total of $61?
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最佳解答:1. Let y be the age of the girl, then (62 - y) be the age of her mother y -2 = 1/2 (62 - y) 2(y - 2) = 62 - y 2y - 4 = 62 - y 3y = 66 y = 22 Hence, the age of the girl is 22 & the age of her mother is (62 - 22) = 40. 2. Let y be the total amount of money, y/10 + 30 = y/8 4y + 1200 = 5y y = 1200 Hence, the total amount of money is $1200. 3. Let y be Peter has, then ( y - 9 ) be Paul has & y/3 be Philip has, y + ( y - 9 ) + y/3 = 61 2y - 9 + y/3 = 61 2y + y/3 = 70 6y + y = 210 7y = 210 y = 30 Hence, Peter has $30, Paul has (30 - 9) = $21, Philip has (30/3) = $10
其他解答:
1)Let x be the girl's age and y be her mother's age x-y/2=2...(1) x+y=62...(2) From (2) x=62-y...(3) Put (3) into (1), 62-y-y/2=2 124-2y-y=4 -3y=-120 y=40 Put y=40 into (2) x+40=62 x=22 Therefore, the girl is 22 years old and her mother is 40 years old. 2)Because each of the 8 attendees gets $30 more after two absent, so two absent have 8*30=$240 and each of them have $120 so the total amount of money is $120*10=$1200 3)Let x be the money that Peter has, y be the money that Paul has and z be the money that Philip has x-y=9...(1) x/3=z...(2) x+y+z=61...(3) From (1), y=x-9...(4) Put (4) and (2) into (3) x+(x-9)+x/3=61 3x+3x-27+x=183 7x-27=183 7x=210 x=30 Put x=30 into (1), 30-y=9 -y=-21 y=21 Put x=30 into (2), 30/3=z z=10 Therefore, Peter has $30, Paul has $21 and Philip has $10.34CDDE348BEB263C
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