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Given : (1) When time = 0, displacement = 0 (2) When displacement = 1, velocity = 0 (3) Acceleration = - g = - 9.8 Find : Time when displacement = - 10. (Ans. correct to 2 d.p.)
最佳解答:
SInce you did not give any unit to the physical quantities, I assume they are in the usual SI units. Hence, at time = 0 s, displacement = 0 m and at displacement = 1m, velocity = 0 m/s Using the equation: v^2 = u^2 + 2a.s with v = 0 m/s, a = -g(=-9.8 m/s2), s = 1 m, u =? hence, 0 = u^2 + 2.(-9.8).(1) u = 4.427 m/s Apply equation: s = ut + (1/2)at^2 to the whole journey with s = -10 m, u = 4.427 m/s, a = -g(=-9.8 m/s2), t =? hence, -10 = 4.427t + (1/2).(-9.8)t^2 solve for t gives t = 1.95 s or -1.05 s(rejected) The time required is thus 1.95 s
其他解答:D1B39E80075704FD
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Mechanics - Linear Motion發問:
Given : (1) When time = 0, displacement = 0 (2) When displacement = 1, velocity = 0 (3) Acceleration = - g = - 9.8 Find : Time when displacement = - 10. (Ans. correct to 2 d.p.)
最佳解答:
SInce you did not give any unit to the physical quantities, I assume they are in the usual SI units. Hence, at time = 0 s, displacement = 0 m and at displacement = 1m, velocity = 0 m/s Using the equation: v^2 = u^2 + 2a.s with v = 0 m/s, a = -g(=-9.8 m/s2), s = 1 m, u =? hence, 0 = u^2 + 2.(-9.8).(1) u = 4.427 m/s Apply equation: s = ut + (1/2)at^2 to the whole journey with s = -10 m, u = 4.427 m/s, a = -g(=-9.8 m/s2), t =? hence, -10 = 4.427t + (1/2).(-9.8)t^2 solve for t gives t = 1.95 s or -1.05 s(rejected) The time required is thus 1.95 s
其他解答:D1B39E80075704FD
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