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我想要數學証明題目的理由(到中4)(中英對照唔該)
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因為我form2 唔知中3中4教咩 但係上面幾題我ok ∠ sum of Δ: ΔABC Let AD be parallel to BC at A, and CD be parallel to AB at C Produce CB to E ∠EBC = 180° = ∠EBA + ∠ABC (adj. ∠s on st. line) ∠EBA = ∠DAB (parallel line EC, AD) = ∠DAC + ∠BAC ∠DAC = ∠ACB(parallel line AB, CD) ∠EBC = 180° = ∠EBA + ∠ABC = ∠DAB + ∠ABC = ∠DAC + ∠BAC + ∠ABC = ∠ACB + ∠BAC + ∠ABC = ∠ sum of Δ = 180° ext. ∠ of Δ: Same positions of ABCE and name in Part ∠ sum of Δ. ext. ∠ of ∠B = ∠EBA ∠EBA = ∠EBC - ∠ABC (proved) = 180° - ∠ABC = ∠ sum of Δ- ∠ABC = ∠ACB + ∠BAC According to the uppers, ext. ∠ of ΔABC = ext. ∠ of ∠A + ext. ∠ of ∠B + ext. ∠ of ∠C = (∠ABC + ∠ACB + ∠BAC) * 2 = ∠ sum of Δ * 2 adj. ∠s on st. line: Same position in Part ∠ sum of Δ. EBC is st. line. ∠EBC = 180° (st. line ∠) = ∠EBA + ∠ABC (proved, adj. ∠s on st. line) ∴adj. ∠s on st. line = 180° 呼~ 打完 唔打中文 2007-10-12 23:27:57 補充： 要中文自己查la=.=
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我想要數學証明題目的理由(到中4)(中英對照唔該)
發問:
此文章來自奇摩知識+如有不便請留言告知
例如以下的 ∠ sum of Δ三角形內角和 ext. ∠ of Δ三角形外角和 adj. ∠s on st. line直線上的鄰角 到中四學左既都比曬我知唔該..最佳解答:
因為我form2 唔知中3中4教咩 但係上面幾題我ok ∠ sum of Δ: ΔABC Let AD be parallel to BC at A, and CD be parallel to AB at C Produce CB to E ∠EBC = 180° = ∠EBA + ∠ABC (adj. ∠s on st. line) ∠EBA = ∠DAB (parallel line EC, AD) = ∠DAC + ∠BAC ∠DAC = ∠ACB(parallel line AB, CD) ∠EBC = 180° = ∠EBA + ∠ABC = ∠DAB + ∠ABC = ∠DAC + ∠BAC + ∠ABC = ∠ACB + ∠BAC + ∠ABC = ∠ sum of Δ = 180° ext. ∠ of Δ: Same positions of ABCE and name in Part ∠ sum of Δ. ext. ∠ of ∠B = ∠EBA ∠EBA = ∠EBC - ∠ABC (proved) = 180° - ∠ABC = ∠ sum of Δ- ∠ABC = ∠ACB + ∠BAC According to the uppers, ext. ∠ of ΔABC = ext. ∠ of ∠A + ext. ∠ of ∠B + ext. ∠ of ∠C = (∠ABC + ∠ACB + ∠BAC) * 2 = ∠ sum of Δ * 2 adj. ∠s on st. line: Same position in Part ∠ sum of Δ. EBC is st. line. ∠EBC = 180° (st. line ∠) = ∠EBA + ∠ABC (proved, adj. ∠s on st. line) ∴adj. ∠s on st. line = 180° 呼~ 打完 唔打中文 2007-10-12 23:27:57 補充： 要中文自己查la=.=
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